a number consists of two digits the digit at the ones place is three times the digit at the tens place if 36 is added to the number the digit are reversed find the number
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Man! I don't understand this qs
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let's begin
if,
the single local digit = x
the tenth local digit = y
so,the number is 10y + x
and y = 3x..........(i)
10y + x + 36 = 10x + y
or,10y + x - 10x - y = -36
or,9y - 9x = -36
or,9(y -x) = -36
or,y - x = -36/-9
or,y- x = 4........(ii)
if, y = 3x then
3x - x = 4
or,2x = 4
or,x = 4/2
or,x = 2
if,x = 2 then,
y = 3×2
y = 6
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