Question

A number consists of two digits the digit at the ones place is 3 times the digit at 10th place if 36 is added to the number the digits are reserved find the numbers

Answer 1

Let the two digit no be 10x + y
3y = x
10x + y + 36 = 10y + x
10x - x + y - 10y = -36
9x - 9y = 36
9(x - y) = 36
x - y = 4
putting value of x
3y - y = 4
2y = 4
y = 2
Putting value of y in x - y
x - 2 = 4
x = 6
The two digit no. formed = 10x + y
= 10 × 6 + 2
= 60 + 2
= 62 ANS