Question

A number consists of two digits. The digit at the ten's place is three more than two times the digit at the unit's place the number formed by reversing the digits is 8 more than one-third of the original number. Find the original number

Answer 1

let the no. be 10x+y
given tht y+3=x
thus the no is 10(y+3)+y
also 10y+(y+3)+8=1/3*10(y+3)+y
get the value of y from the equation above and the get the value of x

Answer 2

Let the number at unit place be x
And, the number at tens place 2x + 3

Now, the number formed by reversing the digit =10 x + ( 2x + 3 )

According to question,

10x + ( 2x + 3) -8 = 1/3 10(2x + 3) + x

Solve the equation.

Hope it helps......