Question

A number consists of two digits. The digit at the ten’s place is two times the digit at the one’s place. The number formed by reversing the digits is 36 less than the original number. Then the original number is

Answer 1

Answer:

84

Step-by-step explanation:

Let the digit at the unit's place be x

Then digit at the ten's place=2x

Number=10(digit at ten's  place)+Digit at unit's place

=10(2x)+x=20x+x=21x

Number formed by reversing the digits=10×x+2x=10x+2x=12x

New number= (old number)−36

                      21x-36=12x

                       9x=36

                       x=4=number at unit place

                       2×4=8=2x=number at ten's place

original number =84