a number consists of two digits.the digit at the tens place is two times the digit at the ones place. the number formed by reversing the digits is 27 less than the original number.find the original number.! plzzz help me out...fast...onot correct answer please....
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Answer:
Step-by-step explanation:
Let the digit at ten's place = 2x
Let the digit at ones place = x
According to the question:-
10(2x)+x =10(x)+2x+27
=>20x+x = 10x +2x +27
=>21x = 12x +27
=>21x-12x = 27
=>9x = 27
=>x = 27/9
=> x = 3
Digit at ones place = 3
Digit at ten's place = 2x = 2*3 = 6
Original number = 63
Pls mark this answer as the Brainliest!!!
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