A number consists of two digits.The digit at the unit's place is 3 times the digit at the ten's place.If 36 is added to the number,the digits are reversed.Find the number.Answer with steps.
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Let the digits be x and y
y=3x
10x+y+36=10y+x
10x-x+y-10y=-36
9x-9y=-36
x-y=-4
x-3x=-4
-2x=-4
x=2
y=2 x=6
=26
y=3x
10x+y+36=10y+x
10x-x+y-10y=-36
9x-9y=-36
x-y=-4
x-3x=-4
-2x=-4
x=2
y=2 x=6
=26
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