A number consists of two digits. The digit in ten's place exceeds the digit in unit's place by 3. The sum of the digits is 1/7 of the number. Find the number.
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Let the digit in the units place =x
Let the digit in the tens place =x+4
∴ The number is 10(x+4)+x=10x+40+x=11x+40
Sum of the digits =x+x+4=2x+4
Given, 2x+4=
7
1
(11x+40)
⇒14x+28=11x+40
⇒3x=12
⇒x=4
∴ the number is 11×4+40=44+40=84
ur answer is 84
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