Question

A number consists of two digits. The digit in ten's place exceeds the digit in unit's place by 3. The sum of the digits is 1/7 of the number. Find the number.​

Answer 1

Answer:

Let the digit in the units place =x

Let the digit in the tens place =x+4

∴ The number is 10(x+4)+x=10x+40+x=11x+40

Sum of the digits =x+x+4=2x+4

Given, 2x+4=

7

1

(11x+40)

⇒14x+28=11x+40

⇒3x=12

⇒x=4

∴ the number is 11×4+40=44+40=84

ur answer is 84