A number consists of two digits. The digit in the tens place exceeds the digit in the units place
by 4. The sum of the digit is of the number. The number is
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Let the tens digit is X
Unit digit= X-4
Number
X×10 +X-4
ATQ
sum of number = 1/7 of number
X+X-4 = 1/7 × 11X-4
14X-28 =11X-4
3X= 24
X=8
So the number is
(8×10 +8-4 ) =84
Unit digit= X-4
Number
X×10 +X-4
ATQ
sum of number = 1/7 of number
X+X-4 = 1/7 × 11X-4
14X-28 =11X-4
3X= 24
X=8
So the number is
(8×10 +8-4 ) =84
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