A number consists of two digits. the ones digit is 1/2 of the tens digit. find the number if the sum of the digit is 6.
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Answer:
Let us assume x and y are the digits of the number.
Therefore, the two-digit number is 10x + y
Given:
y = 1/2x ------------1
Also given:
x + y = 6 -------------2
Substitute the value of y from eqn1 in eqn 2
x + (1/2)x = 6
(3/2)x = 6
3x = 12
x = 4
Therefore, y = 1/2 * 4 = 2
The two-digit number is = 10x + y = (10*4) + 2 = 42
Step-by-step explanation:
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