Question

A number consists of two digits. The sum of digits is 13. If we change
the places of digits, the new number is increased by 45. Find the
number.​

Answer 1

$\purple{ \mathfrak{ \large{ \underbrace{Solution}}}}$

Let the original number by xy

According to the question,

x + y = 13 {equation 1}

yx = xy + 45 {equation 2}

Noting that the value of "xy" is 10x + y

and the value of "yx" is 10y + x we have:

10y + x = 10x + y + 45

working this down

9x - 9y = -45

Thus we have 2 simultaneous equations we can use

to solve the system

x + y = 13

9x - 9y = -45

multiply 1st equation by 9 and add equations

9x + 9y = 117

9x - 9y = -45

---------------

18x = 72

x = 4

Since x + y = 13 and x = 4...

y = 9

Hence the number is 49✅

❣Hope this helps you mate!!✌

Answer 2

Answer:

ans is 49

Step-by-step explanation:

4+9=13

if the places of digits changed

then,the no. is 94

94-49=45

hence ,the ans is 49