a number consists of two digits the sum of the digit is 5 and if the left digit b increase by one it will be equal to 1 by 8 of the number find the number
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Let the two digits be x and y.
x at ten's place and y at unit's place.
The number becomes 10x + y
.°. x + y = 5
New ten's digit = x + 1
x + 1 = (10x + y) /8
Substituting x + y by 5,
8x + 8 = 9x + 5
x = 3
y = 5 - 3 = 2
The answer is, thus, = 32
Well, I am not completely sure about the answer because the question is not clear, especially, what is equal to 1 by 8 of the number.
x at ten's place and y at unit's place.
The number becomes 10x + y
.°. x + y = 5
New ten's digit = x + 1
x + 1 = (10x + y) /8
Substituting x + y by 5,
8x + 8 = 9x + 5
x = 3
y = 5 - 3 = 2
The answer is, thus, = 32
Well, I am not completely sure about the answer because the question is not clear, especially, what is equal to 1 by 8 of the number.
AniketBest:
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