a number consists of two digits,the sum of which is 5. if the digit in the ten place is increased by 1. the digit will be equal to 1/8 of the given number. find the number
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let the number of 1st digit=X
and the other number in 10th digit=X+1
A.T.Q
(X+1)+X=5
X+1+X=5
2x+1=5
2x=5-1
2x=4
X=4/2
X=2
hence,the no. in 1st digit =X=2
and 2nd no. in 10th digit =X+1=2+1=3
So,answer is 32
and the other number in 10th digit=X+1
A.T.Q
(X+1)+X=5
X+1+X=5
2x+1=5
2x=5-1
2x=4
X=4/2
X=2
hence,the no. in 1st digit =X=2
and 2nd no. in 10th digit =X+1=2+1=3
So,answer is 32
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