A number consists of two-digits, the sum of whose digits is 9. If 4 times the original number
is equal to 7 times the number obtained by reversing the digits, find the original number.
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Answer:
x=6 and y=3 will be the answer
Step-by-step explanation:
let the ones digit be y and the tens digit be x.
Case 1st,
x+y=9.............eq1
Case 2nd,
4(10x+y)=7(10y+x)
40x+4y=70y+7x
40x-7x=70y-4y
33x=66y
33x-66y=0
33(x-2y)=0
x-2y=0............eq2
subtracting equation 2nd from equation 1st
x-2y=0
x+y=9
- - -
_______
-3y=-9
y=3
putting the value of y in equation 1st
x+y=9
x+3=9
x=9-3
x=6
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