Question

A number consists of two-digits, the sum of whose digits is 9. If 4 times the original number is equal to 7 times the number obtained by reversing the digits, find the original number.

Answer 1

Answer:

63

Step-by-step explanation:

Let the tens place of number = x

And let the one's place of number = y

The, the number = 10x + y

Given, x + y = 9

Given, 4(10x + y) = 7(10y + x)

40x + 4y = 70y + 7x

40x - 7x = 70 y - 4y

33x = 66y

∴ x = 2y

Now using the equation, x + y = 9

2y + y = 9

3y = 9

Therefore, y = 3 , x = 2y = 6

Original number = 10x + y = 60 + 3 = 63

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