Question

a number consists of two digits whose product is 30 if unit's digit is subtracted from ten's digit 1 is obtained find the number

Answer 1

Answer:

65

Step-by-step explanation:

Let us assume that the unit's digit and the ten's digit of the two-digit number are y and x respectively.

So, the number will be given by (10x+y).

Given that the product of the digits is 30 and the ten's digit is one more than the unit's digit.

Hence, xy=30 ...... (1) and  

x= y+1 ...... (2)

So, solving equations (1) and (2) we get,

y(y+1) = 30

⇒ y²+y = 30

⇒ y²+y-30 =0

⇒ (y+6) (y-5) =0

⇒ y=5 {Neglecting the negative root of y as y can not be negative}

So, from equation (2), x= 5+1 =6.

Therefore, the number is (10x+7) = (10*6+5) = 65. (Answer)

Answer 2

Answer:

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