Question

A number consists of two digits whose sum if 5. When the digits are reversed, the number becomes greater by 9. Find the number

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

Solution :-

Let the required number be x.

And the ones place digit be y.

Number = 10x + y

Reversed Number = 10y + x

According to the Question,

⇒ x + y = 5 .... (i)

⇒ (10x + y) + 9 = (10y + x)

⇒ 10x + y + 9 = 10y + x = 0

⇒ 9x - 9y= - 9

⇒ x - y= - 1.... (ii)

Solving Eq (i) &(ii), we get

⇒ x + y = 5

⇒x - y = - 1

⇒ 2x = 4

⇒ x = 4/2

⇒ x = 2

Putting x's value in Eq (i), we get

⇒ x + y = 5

⇒ 2 + y = 5

⇒ y = 3

Number = 10x + y = 10(2) + 3 = 23

Hence the required number is 23.