Question

A number consists of two digits whose sum is 10.When 36 is added the number is reversed

Answer 1

Answer

Let the number be xy = 10x+y

Given x + y = 10 (i)

and

10x + y + 36 = 10y + x (digits of original number reversed by adding 36)

9x-9y = -36

x-y = -4(ii) dividing throughout by 9

Adding (i) and (ii)

x + y = 10

x-y = -4

We get,

2x = 6

OR

x=3

Subsituting of x in (i)

3 + y = 10

or y = 10 - 3 = 7

Therefore, The original number xy(10x + y) = 30+7 = 37

Check:-37 + 36 = 73

Hope it will help you^____^