Question

a number consists of two digits whose sum is 10the number obtained on reversing the order of the digits of the given number exceeds the given number by 36.find the given number

GIVE A BRIEF EXPLANATION!!!​

Answer 1

Step-by-step explanation:

let,

x=tens digit

y=ones digit

x+y=10

required number=10x+y

number obtained by reversing digits=10y+x

10y+x=36+10x+y

9y=9x+36

-9x+9y=36

add

-x+y=4+

x+y=10

we get

y=7

substitute y in x+y=10

x+7=10

x=3

so number =37