A number consists of two digits whose sum is 11.if 27 is added to the number then the digits change their places. find the number.
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Let to be 10'digit no x
"""""""""""1'unit no y
required no=10x+y
reverse no=10y+x
A/q
x+y=11------(1)
Again 10x+y+27=10y+x
10x-x+y-10y=-27
9x-9y=-27
9(x-y)=-27
x-y=-3. ------(2)
by elimination method for solving this question.
x+y=11
x-y=-3
----------
-2y=-14
y=14/2
y=7
now Pu t value of y
x+y=11
x+7=11
x=11-7
x=4
now no be
10x+y
10(4)+7
40+7
47
that's all
you have any problem you ask.....
"""""""""""1'unit no y
required no=10x+y
reverse no=10y+x
A/q
x+y=11------(1)
Again 10x+y+27=10y+x
10x-x+y-10y=-27
9x-9y=-27
9(x-y)=-27
x-y=-3. ------(2)
by elimination method for solving this question.
x+y=11
x-y=-3
----------
-2y=-14
y=14/2
y=7
now Pu t value of y
x+y=11
x+7=11
x=11-7
x=4
now no be
10x+y
10(4)+7
40+7
47
that's all
you have any problem you ask.....
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