Question

A number consists of two digits whose sum is 5 and the digits are reversed the number becomes greater by 9 find the number

Answer 1

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Answer 2

Hey

Here is your answer,

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Let the number be 10t+u where t is the tens and u is the units digit.
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Equations:

t + u = 5
10u+t = 10t+u +9
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Simplify :
t + u = 5
9u - 9t = 9x

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t + u = 5
-t+u = 9
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Add:
2u = 14
u = 7
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But, if u = 7, then t= -2
and that makes no sense
for a 2-digit number.
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Hope it helps you!