Question

a number consists of two digits whose sum is 5 when the digits are reversed the number becomes greater by 9 .find the number​

Answer 1

Answer:

32

Step-by-step explanation:

Let the tens digit be a and ones digit be b.

Then a + b = 5 (equation 1) and

10a + b — 9 = 10b + a (equation 2)

9a — 9 = 9b

a — 1 = b

a — b = 1 (equation 3)

But a + b = 5 (equation 1)

Adding equation 3 and equation 1 gives

2a = 6, which means a = 3 and b = 2

In other words, the number is 32