A number consists of two digits whose sum is 5. When the digits are reversed,
the number becomes greater by 9. Find the number.
Answers
Answered by
6
Answer:
23
Step-by-step explanation:
Let the digits in the tens be x and ones place be y.
Hence the number is 10x+y
By reversing 10y+x
Sum of digit =5
⇒x+y=5⟶(i)
Also that when 9 is added to the number the digits get interchanged.
∴(10x+y)+9=(10y+x)
10x+y+9=10y+x=0
9x−9y=−9
x−y=−1⟶(ii)
Adding (i) &(ii) we get ,
⇒x+y=5
⇒x−y=−1
⇒2x=4
⇒x=2
Put x=2 in x+y=5
∴2+y=5
⇒y=3
Hence the no: is 23.
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Answered by
1
Answer:
OK
OK OK OK
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