a number consists of two digits whose sum is 6.if 18 is added to the number, it's digits are reversed. find the number
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Q) A number consists of two digits whose sum is 6 if 18 is added to the number, it's digits are reversed. find the number.
S) → let the digit at tens place be x.
So, as we've been told that the sum of two digits is 6 , so if digit at tens place is x then digit at ones place = 6-x
The number formed is 10x + 6-x = 9x+6
When we reverse the digits → 10(6-x) + x
= 60-10x+x = 60-9x
According To Question→
9x+6 + 18 = 60-9x
or, 9x+24 = 60-9x
or, 9x+9x = 60-24
or, 18x = 36
or, x = 36/18
or, x = 2
So, the number is 9x+6 = 9(2)+6 = 18+6 = 24
Answer→ The number is 24.
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S) → let the digit at tens place be x.
So, as we've been told that the sum of two digits is 6 , so if digit at tens place is x then digit at ones place = 6-x
The number formed is 10x + 6-x = 9x+6
When we reverse the digits → 10(6-x) + x
= 60-10x+x = 60-9x
According To Question→
9x+6 + 18 = 60-9x
or, 9x+24 = 60-9x
or, 9x+9x = 60-24
or, 18x = 36
or, x = 36/18
or, x = 2
So, the number is 9x+6 = 9(2)+6 = 18+6 = 24
Answer→ The number is 24.
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47
Hey.....here is ur answer
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