Math, asked by ruchiroopa30, 11 months ago

a number consists of two digits whose sum is 7 if 9 is added to the number the digits change their places then the value is ​

Answers

Answered by pradeeprajputrmp
12

Answer:

34

Step-by-step explanation:

Let the first digit of the number be x

The second digit =7-x

the number thus formed will be

10(x)+(7-x) ( first digit place value is 10 times in tens place)

=10x+7-x

According to the question

10x+(7-x)+9= 10(7-x)+x

10x+7-x+9=70-10x+x

10x-x+7+9= 70-9x

9x+16=70-9x

9x+9x= 70-16

18x=54

x= 54÷18

x=3

So first digit =3

and second digit will be 7-3=4

The number thus formed will be

10(3)+4 ) ( first digit place value is 10 times in tens place)

=34

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