a number consists of two digits whose sum is 7 if 9 is added to the number the digits change their places then the value is
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12
Answer:
34
Step-by-step explanation:
Let the first digit of the number be x
The second digit =7-x
the number thus formed will be
10(x)+(7-x) ( first digit place value is 10 times in tens place)
=10x+7-x
According to the question
10x+(7-x)+9= 10(7-x)+x
10x+7-x+9=70-10x+x
10x-x+7+9= 70-9x
9x+16=70-9x
9x+9x= 70-16
18x=54
x= 54÷18
x=3
So first digit =3
and second digit will be 7-3=4
The number thus formed will be
10(3)+4 ) ( first digit place value is 10 times in tens place)
=34
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