Question

A number consists of two digits whose sum is 8 if 18 is added to the number its digits are reversed the number

Answer 1

Answer:

Required number is 35

Step-by-step explanation:

Let the digit at unit's place be x

Let the digit at ten's place be y

Number = 10y + x

Given that sum of digits of number is 8

We have

x + y = 8 ---------- (1)

Also, given that if 18 is added to the number, its digits are reversed.

When digits are reversed, number = 10x + y

Thus, we get

10y + x  + 18 = 10x + y

(10x - x) + (y - 10y) = 18

9x - 9y = 18

x - y = 2 --------- (2)

Solving (1) and (2), we get

x + y = 8

x - y = 2

-----------------

2x = 10

x = 10/2

x = 5

Putting x in (1),we get

5 + y =8

y = 8 - 5

y = 3

Thus, required number  = 10(3) + 5 = 35