A number consists of two digits whose sum is 8. if 18 is added to the number its digit are reversed find the answer
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Solution:-
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Let the -
- Ten's digit number be M
- One's digit number be N
- Sum of numbers is 8.
According to question
⇒ M + N = 8
⇒ M = 8 - N
If 8 is added to the number the digits got reversed.
Then,
Original number = 10M + N
Revered number = 10N + M
According to question
⇒ 10N + M = 10M + N + 18
⇒ 10N - N + M - 10M = 18
⇒ 9N - 9M = 18
⇒ N - M = 2
⇒ N - (8 - N) = 2
⇒ N - 8 + N = 2
⇒ 2N = 10
⇒ N = 5
Substitute value of N = 5 in equation 1
⇒ M = 8 - 5
⇒ M = 3
Original number = 10M + N
⇒ 10(3) + 5
⇒ 30 + 5
⇒ 35
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