Question

A number consists of two digits whose sum is 8. if 18 is added to the number its digit are reversed find the answer

Answer 1

Solution:-

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Let the -

• Ten's digit number be M

• One's digit number be N

• Sum of numbers is 8.

According to question

⇒ M + N = 8

⇒ M = 8 - N

If 8 is added to the number the digits got reversed.

Then,

Original number = 10M + N

Revered number = 10N + M

According to question

⇒ 10N + M = 10M + N + 18

⇒ 10N - N + M - 10M = 18

⇒ 9N - 9M = 18

⇒ N - M = 2

⇒ N - (8 - N) = 2

⇒ N - 8 + N = 2

⇒ 2N = 10

⇒ N = 5

Substitute value of N = 5 in equation 1

⇒ M = 8 - 5

⇒ M = 3

Original number = 10M + N

⇒ 10(3) + 5

⇒ 30 + 5

⇒ 35

$\huge\boxed{35}$