A number consists of two digits whose sum is 8.If 18 is added to the number its digits are reversed.Find the number.
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Let the digit at ones place be ‘x’
Then the digit at tens place = 8 – x (sum of the two digits is 8)
Therefore number 10 (8 – x) + x = 80 – 10x + x = 80 – 9x —— (1)
Now, number obtained by reversing the digits = 10 ×(x) + (8 – x)
= 10x + 8 – x = 9x + 8
It is given that if 18 is added to the number its digits are reversed
∴ number + 18 = Number obtained by reversing the digits
⇒ (80 – 9x) + 18 = 9x + 8
98 – 9x = 9x + 8
98 – 8 = 9x + 9x
90 = 18x
x =
90
18 = 5
By substituting the value of x in equation (1) we get the number
∴ Number = 80 – 9 × 5 = 80 – 45 = 35.
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