Question

A number consists of two digits whose sum is 8. if 18 is added to the number its digits are
reversed. Find the number
​

Answer 1

Answer:

Let one of the digit of the two digit number is x.

then problem other number is (8−x)

So,we get the equation

$= > 10x + (8 - x) + 18 = 10(8 - x) + x$

$= > 10x + 8 - x + 18 = 80 - 10x + x$

$= > 9x + 26 = 80 - 26$

$= > 18x = 54$

$x = \frac{54}{18}$

$x = 3$

Then,

The digit in tens place is 3

The digit in ones  place is (8−3=5), then the number is 35 and when 18

is added the result is 53 the digits interchange their position in the  new number.

Then,

We get the number is 35

Answer 2

Answer:

Let the one number be x and another number be 8 - x.

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10x + (8 - x) + 28 = 10(8 - x) + x

10x + 8 - x + 18 = 80 - 10x + x

9x + 26 = 80 - 9x

9x + 9x = 80 - 26

18x = 54

x = 3

Therefore,

One number = x = 2

Other number = (8 - x) = 8 - 3 = 5