Question

A number consists of two digits whose sum is 8. If 18 is added to the number its digits are
reversed. Find the number.
find
​

Answer 1

Answer:

35

Step-by-step explanation:

Let one digit of the number be x , then its ten  digits digits will be (8−x) . 

So , given number =10(8−x)+x 

                                 =80−10x+x 

                              =80−9x

Now if digits are reversed  , then Number obtained  

                                 =10x+(8−x)

                                 =10x+8−x

                                 =9x+8

According to question 

        (80−9x)+18=9x+8

         98−9x=9x+8 

         90=18x

           x=5

⇒ given number  =80−9x

                                          =80−9×5      

                                          =80−45 

                                          =35         

Answer 2

Answer:

Let one digit of the number be x , then its ten digits digits will be (8−x) .

So , given number =10(8−x)+x

=80−10x+x

=80−9x

Now if digits are reversed , then Number obtained

=10x+(8−x)

=10x+8−x

=9x+8

According to question

(80−9x)+18=9x+8

98−9x=9x+8

90=18x

x=5

⇒ given number =80−9x

=80−9×5

=80−45

=35

∴ the number is 35