a number consists of two digits whose sum is 8 if 18 is added to the number its digit are reveresed find the number
Answers
Answered by
0
Let one of the digit of the two digit number is x.
then problem other number is (8−x)
So,we get the equation
10x+(8−x)+18=10(8−x)+x
10x+8−x+18=80−10x+x
9x+26=80−26
18x=54
x= 54/18
x=3
Then,
The digit in tens place is 3
The digit in ones place is (8−3=5), then the number is 35 and when 18
is added the result is 53 the digits interchange their position in the new number.
Then,
We get the number is 35.
Similar questions