Question

a number consists of two digits whose sum is 8 if 18 is added to the number its digit are reveresed find the number​

Answer 1

Let one of the digit of the two digit number is x.

then problem other number is (8−x)

So,we get the equation

10x+(8−x)+18=10(8−x)+x

10x+8−x+18=80−10x+x

9x+26=80−26

18x=54

x= 54/18

x=3

Then,

The digit in tens place is 3

The digit in ones place is (8−3=5), then the number is 35 and when 18

is added the result is 53 the digits interchange their position in the new number.

Then,

We get the number is 35.