Question

a number consists of two digits whose sum is 8 if 18 is added to the number it's digits are reversed find the number and check also​

Answer 1

Answer:

Let one of the number be x

And the other number be 8 - x

According to the question

⇒ 10x + (8 - x) + 18 = 10(8 - x) + x

⇒ 10x + 8 - x + 18 = 80 -10x + x

⇒ 9x + 26 = 80 - 9x

⇒ 9x + 9x = 80 - 26

⇒ 18x = 54

⇒ x = 54/18

⇒ x = 3

One Number = x = 3

Other number = 8 - x = 8 - 3 = 5

Hence, the number is 35

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Answer 2

Answer: Step-by-step explanation:

Let one digit of the number be x, then its ten digits will be (8−x).  

So, given number =10(8−x)+x  

                                =80−10x+x  

                             =80−9x  

Now if digits are reversed, then Number obtained  

                                =10x+(8−x)

                                =10x+8−x

                                =9x+8  

According to question  

       (80−9x)+18=9x+8

        98−9x=9x+8  

        90=18x

          x=5  

⇒ given number  =80−9x

                             =80−9×5      

                             =80−45  

                             =35          

∴ the number is 35

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