Question

A number consists of two digits whose sum is 8. If 18is added to the number its digits are reversed. Find the number.

Answer 1

Hey

Here is your answer,

Let digits be x and y

Number = 10x + y

Reversed Number = 10y + x

According to question,

x + y = 8 ..............1

and

10x + y + 18 = 10y + x

=> 9x - 9y = -18

=> x - y = -2 ..........2

Adding 1 and 2

2x = 6

=> x = 6/2

=> x = 3

and y = 5

So, the number is 35

Hope it helps you!

Answer 2

Step-by-step explanation:

Let the one number be x and another number be 8 - x.

$\underline{ \large \purple{ \mathscr{\dag\:A \bf{ccourding} \: to \: \mathscr {Q} \bf{uestion} ....}}} </p><p>$

10x + (8 - x) + 28 = 10(8 - x) + x

10x + 8 - x + 18 = 80 - 10x + x

9x + 26 = 80 - 9x

9x + 9x = 80 - 26

18x = 54

x = 3

Therefore,

• One number = x = 2
• Other number = 8 - 3 = 5