A number consists of two digits whose sum is 9 if 27 subtracted from the number its digits are reversed .Find the number.
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63
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A number consists of two digits whose sum is 9. If 27 is subtracted from the number its digits are reversed. Find the number.
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Let the number =ab=10a+b
Sum of digits =9
a+b=9
number −27=number with reversrd digits
10a+b−27=10b+a
9(a−b)=27
a−b=3
(a+b)+(a−b)=9+3⇒a=6,b=3
∴ Required number is 63
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