Math, asked by swe16, 10 months ago

A number consists of two digits whose sum is 9. If 27 is subtracted from the number its

digits are reversed. Find the number.

Answers

Answered by amritkaurraghuvir22

Answer:

Step-by-step explanation:

Let us assume, x and y are the two digits of the two-digit number

Therefore,

the two-digit number = 10x + y

reversed number = 10y + x

Condition I:

x + y = 9 -------------(1)

Condition II

10x + y - 27 = 10y + x

9x - 9y = 27

x - y = 3 --------------(2)

Adding equation 1 and equation 2

x + y = 9

x - y = 3

-----------

2x = 12

x = 6

Therefore, y = 9 - x = 9 - 6 = 3

The two-digit number = 10x + y = 10*6 + 3 = 63

Answered by arshbbcommander

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Let the two digit number b 10x + y

Where x is digit at tens place and y at ones place.

acc. to que.

Case 1

x+y=9

y=9-x.....1)

Case 2

(10x + y )-27 = 10y + x

(10x+9-x)-27=10(9-x)+x

9x+9-27= 90-10x + x

9x+9x=90-9+27

18x=108

x=6

put x =6 in eqn 1

y=9-6=3

y=3

Thus number is 63

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...Hope it helps....

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A number consists of two digits whose sum is 9. If 27 is subtracted from the number itsdigits are reversed. Find the number.​

Answers

x=6

y=3

Thus number is 63

A number consists of two digits whose sum is 9. If 27 is subtracted from the number its

digits are reversed. Find the number.