A number consists of two digits whose sum is 9.if 27 is subtracted from the number its digits are reversed. Find the numbers? Jo
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the answer is 7 = ( 63 )
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Let the ten's digit be x and one's digit be y
According. to question:-
x+y=9______________(1)
also the original no. will be:-10x+y
Now also the reversed no. will be 10y+x
According. to question
10x+y-27=10x+y
9x-9y=27
9 (x-y)=27
x-y=27/9
x-y=3_______________(2)
from eqn 1 we get x=9-y
now putting the value of x in eqn 2 we get :-
9-y-y=3
-2y=-6
y=3
now therfore x=9-y=9-3=6
now original no.:-10x+y=10×6+3=63
also reversed no.:-10y+x=10×3+6=36
According. to question:-
x+y=9______________(1)
also the original no. will be:-10x+y
Now also the reversed no. will be 10y+x
According. to question
10x+y-27=10x+y
9x-9y=27
9 (x-y)=27
x-y=27/9
x-y=3_______________(2)
from eqn 1 we get x=9-y
now putting the value of x in eqn 2 we get :-
9-y-y=3
-2y=-6
y=3
now therfore x=9-y=9-3=6
now original no.:-10x+y=10×6+3=63
also reversed no.:-10y+x=10×3+6=36
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