Question

A number consists of two digits whose sum is 9. if 27 is added to the number the digits change their places. find the number ​

Answer 1

Let the number be A and B

by given condition

a+b=9...........(1)

10a+b+27=10b+a

27=9(b-a)

b-a=3............(2)

add equation (1 )and (2)

a+b+b+a=9+3

2b=12

b=6

b-a=3

6-a=3

a=6-3

a=3

=the number is 36

Answer 2

Answer:

Let the two numbers be a,b.

So, The two digit number will be 10a + b, and reverse of that number = 10b + a

Given, a + b =9 ------------------- (i)

10a + b - 27 = 10b + a

a - b = 3 -------------------- (ii)

On solving (i) and (ii), we get

a = 6

Submit this value in (ii) on we get,

b = 9 - 6 = 3

On submitting the value in above equation we get,

10a + b

= 10 * 6 + 3

=63

So, The number is 63.

Hope this helps!