Question

A number consists of two digits whose sum is 9 . If 27 is subtracted from the number , it's digits are reversed . Find the number ?

Answer 1

let number=10x+y

according to the problem

X+y=9-----(1)

10x+y-27=10y+X

{9x-9y=27}÷9

x-y=3----(2)

Subtract (2) from (1)

X+y=9

x-y=3

(-)(+)(-)

2y=6

y=6/2

y=3

x-y=3

x-3=3

X=3+3

X=6

number=10x+y

=10(6)+3

=60+3

=63

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Answer 2

Hello!

Here is the answer for your question!

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Question:

‣ A number consists of two digits whose sum is 9 . If 27 is subtracted from the number , it's digits are reversed . Find the number ?

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Answer:

step1: ‣ Let the numbers be, x and y,

given,

x + y = 9 (first equation)

and 10x + y -27 = 10y + x (second equation)

from the first equation we can form

x = 9 - y

substituting this value in the second equation

10x + y - 10y - x = 27

10 (9-y) + y - 10y - (9-y) = 27

90 - 10y + y - 10y -9 + y =27

- 18y = -54

y = -54/-18 = 3

y = 3

substituting value of y in equation x + y = 9

x + 3 = 9

x = 9-3 = 6

x = 6

Therefore the number is 63

63 - 27 = 36

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Hope this answer has helped you !