Question

a number consists of two digits whose sum is 9 . if 27 is subtrated from the number its digits are reveresd find the number?​

Answer 1

Step-by-step explanation:

Let the ones digit be x and the tens digit be y.

Then, Number= (10y + x)

A/q

x + y = 9................(i)

And, 10y + x - 27 = 10x + y

=> 10y - y + x - 10x = 27

=> 9y - 9x = 27

=> 9 ( y - x ) = 27

=> y - x = 3...............(ii)

Now, By adding eq. (i) and (ii), we get

x + y = 9

- x + y = 3

----------------

2y = 12

( y = 6 )

Now, put the value of y = 6 in eq. (i)

x + y = 9

x + 6 = 9

x = 9 - 6

( x = 3 )

Then, Number = 10y + x

= 10 ( 6 ) + 3

= 60 + 3

= 63.............Answer.

Hence, The required number is 63.

hope it helps