Question

A number consists of two digits whose sum is 9. If 27 is added to the number, the digits are reversed. Find the number​

Answer 1

Answer:

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Let the two numbers be a,b.

So, The two digit number will be 10a + b, and reverse of that number = 10b + a

                                                                             

                                                                                                

Given, a + b =9                   -------------------  (i)

           10a + b - 27 = 10b + a

           a - b = 3                   --------------------  (ii)

On solving (i) and (ii), we get

    a = 6

Submit this value in (ii) on we get,

          b = 9 - 6 = 3

On submitting the value in above equation we get,

10a + b

= 10 * 6 + 3

=63

So, The number is 63.

Hope this helps!

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Answer 2

Answer:

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Let the two numbers be a,b.

So, The two digit number will be 10a + b, and reverse of that number = 10b + a

Given, a + b =9 ------------------- (i)

10a + b - 27 = 10b + a

a - b = 3 -------------------- (ii)

On solving (i) and (ii), we get

a = 6

Submit this value in (ii) on we get,

b = 9 - 6 = 3

On submitting the value in above equation we get,

10a + b

= 10 * 6 + 3

=63

So, The number is 63.

Step-by-step explanation:

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