Question

a number consists of two digits whose sum is 9 if 27 is subtracted from the number its digit are received find the number​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

We know that one of the digit be ‘x’ The other digit is 9-x So, the two digit number is 10(9-x) + x The number obtained after interchanging the digits is 10x + (9-x) 10(9-x) + x – 27 = 10x + (9-x) Upon simplification, 90 – 10x + x – 27 = 10x + 9 – x -10x + x – 10x + x = 9 – 90 + 27 -18x = -54 x = 54/18 = 9/3 = 3 The two digit number is 10(9-x) + x Substituting the value of x we get, 10(9-x) + x 10(9 – 3) + 3 10(6) + 3 60+3 63 ∴ The number is 63.

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