a number consists of two digits whose sum is 9. if 27 is subtracted from the number its digits are reversed find the number
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Answer:
63.
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Let the units digit be x and tens digit be y.
Original No. = 10y+x
New No. = 10x+y
Given,
Sum of digits = 9
x+y = 9 ..(1)
Original No. -27 = New No.
10y+x - 27 = 10x+y
Solving,
10y-y+x-10x = 27
9y-9x = 27
9(y-x) = 27
y-x = 3
x-y = -3 .. (2)
Adding equation (1) and (2),
2x = 6
x = 3
Substituting value of x in (1),
y = 6
Original No. = 10y+x
Original No. = 60+3
Original No. = 63
Hope it helps
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