Question

a number consists of two digits whose sum is 9 if 27 is subtracted from the number the digits change their places. find the number​

Answer 1

Answer:

Let us assume, x and y are the two digits of the two-digit number

Therefore, the two-digit number = 10x + y and reversed number = 10y + x

Given:

$\boxed{x + y = 9 ----1}$

$\red{★}$Also given:

10x + y - 27 = 10y + x

9x - 9y = 27

x - y = 3 --------------2

Adding equation 1 and equation 2

2x = 12

x = 6

:.Therefore, y = 9 - x = 9 - 6 = 3

$\red{★}$The two-digit number = $\boxed{\fcolorbox{pink}{beige}{10x + y = 10*6 + 3 = 63}}$