Question

A number consists of two digits whose sum is 9.If 27 is subtracted from the number , its digits are reversed . Find the number . Do using Algebraic method.

Answer 1

Answer:

let the two digits if the number us x and y

then according to question , x+y=9

the number is 10x+y

then,

10x+y-27=10y+x

=> 10x-x+y-10y=27

=> 9x-9y=27

=> 9(x-y)=27

=> x-y=27/9

=> x-y=3

=> x=3+y

we know,

x+y=9

=> 3+y+y=9

=> 2y=9-3

=> 2y=6

=> y=6/2

=> y=3

x=3+3=6

the number is 10×6+3=60+3=63

Answer 2

Answer:

63

Step-by-step explanation:

let the digits of number be a and b

a+b=9 _ [i]

a/q,

10a+b-27=10b+a

10a+b-10b+a=27

9a-9b=27

9(a-b)=27

a-b=3 _ [ii]

by adding both equations

a+b=9

+a-b=3

2a=12

a=6

b=3