Question

A number consists of two digits whose sum is 9. If 27 is subtracted from the number its digits are reveased. Find the number.​

Answer 1

Let the number =ab=10a+b

Sum of digits =9

a+b=9

number −27=number with reversrd digits

10a+b−27=10b+a

9(a−b)=27

a−b=3

(a+b)+(a−b)=9+3⇒a=6,b=3

∴  Required number is 63

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