Question

A number consists of two digits whose sum is 9 . if 27 is subtracted from the number its digits are reverse d .find the number

Answer 1

Let the ones digit be x and the tens digit be y.
Then, Number= (10y + x)
A/q
x + y = 9................(i)

And, 10y + x - 27 = 10x + y
=> 10y - y + x - 10x = 27
=> 9y - 9x = 27
=> 9 ( y - x ) = 27
=> y - x = 3...............(ii)

Now, By adding eq. (i) and (ii), we get
x + y = 9
- x + y = 3
----------------
2y = 12
( y = 6 )
Now, put the value of y = 6 in eq. (i)
x + y = 9
x + 6 = 9
x = 9 - 6
( x = 3 )
Then, Number = 10y + x
= 10 ( 6 ) + 3
= 60 + 3
= 63.............Answer.
Hence, The required number is 63.

Answer 2

$\circ\circ\circ\circ\underline{\fbox{\fbox{\fbox{\fbox{\fbox{\Large{\underline{\textbf{SOLUTION}}}}}}}}}\circ\circ\circ\circ$

$Let\:the\:number\:be\:x\:and\:y\\\\\therefore x+y=9.......(1)\\\\10x+y-27=10y+x\\\\\implies9x-9y=27\\\\\implies9(x-y)=27\\\\\implies x-y=3........(2)\\\\\\That\:mean\:by\:adding\:1\:and\:2\\\\we\:obtain,\\\\\\\implies2x=12\\\\\implies x=\frac{12}{2}\\\\\implies x=6\\\\\implies y=3\\\\\\So\:number\:is\boxed{\boxed{63\:answer}}$