A number consists of two digits whose sum is 9.If 27 is subtracted from the number its digits are reversed.Find the numbers
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Answered by
8
let the digit in unit place be x.
and digit in tens place be y
then number =10y+x.
A/q
x+y=9......................1.
and10y+x-27=10x+y
=9y-9x=27
=y-x=3
=-x+y=3.......................2.
adding 1.and 2.
2y=12
y=6
then unit digit=9-6=3
and since number =10y+x
=10(6)+3
=60+3
=63
and digit in tens place be y
then number =10y+x.
A/q
x+y=9......................1.
and10y+x-27=10x+y
=9y-9x=27
=y-x=3
=-x+y=3.......................2.
adding 1.and 2.
2y=12
y=6
then unit digit=9-6=3
and since number =10y+x
=10(6)+3
=60+3
=63
mana99:
Thanks
Answered by
16
Answer:
Given that:-
- Let ones place digit of a number = x
- Sum of 2 digits = 9
- Tens place digit of a number = 9 - x
Then:-
➤10 ( 9 - x ) x = 90 - 10 x - x
= 90 - 9x
Now:-
- 27 is subtracted from the number we get the digits are reversed.
Solution:-
➠ 90 - 9x - 27 = 10(x) + 9 - x
➠ 90 - 9x - 27 = 10x + 9 - x
➠ -9x + 63 = 9x + 9
➠ 63 - 9 = 9x + 9x
➠ 54 = 18x
➠
➠ x = 3
⇨ Once place = 3
⇨ Tens place = 9 - 3
⇨ Tens place = 6.
Step-by-step explanation:
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