Question

A number consists of two digits whose sum is 9.If 27 is subtracted from the number its digits are reversed.Find the numbers

Answer 1

let the digit in unit place be x.
and digit in tens place be y

then number =10y+x.

A/q
x+y=9......................1.

and10y+x-27=10x+y
=9y-9x=27
=y-x=3
=-x+y=3.......................2.

adding 1.and 2.
2y=12
y=6

then unit digit=9-6=3

and since number =10y+x
=10(6)+3
=60+3
=63

Answer 2

Answer:

Given that:-

• Let ones place digit of a number = x

• Sum of 2 digits = 9

• Tens place digit of a number = 9 - x

Then:-

➤10 ( 9 - x ) x = 90 - 10 x - x

= 90 - 9x

Now:-

• 27 is subtracted from the number we get the digits are reversed.

Solution:-

➠ 90 - 9x - 27 = 10(x) + 9 - x

➠ 90 - 9x - 27 = 10x + 9 - x

➠ -9x + 63 = 9x + 9

➠ 63 - 9 = 9x + 9x

➠ 54 = 18x

➠ $\frac{54}{18} = x$

➠ x = 3

$\therefore therefore$

⇨ Once place = 3

⇨ Tens place = 9 - 3

⇨ Tens place = 6.

Step-by-step explanation:

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