a number consists of two digits whose sum is 9 if 27 is subtracted from the original number is digit are interchanged then original number is
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Let the original no be 10x+y
Their sum is 9 mean x+y=9 ......eq 1
If 27 subtracted from the no it get reversed
Mean 10x+y -27=10y+x
X+y=3 .....eq 2
Now you can eleminate them
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Let no at tens place be x
No at one's place be y
Original no be 10x +y
No obtain by reversing the digits 10y +x
According to the given condition
X +y =8
X=8-y eqn 1
According to second condition
10x +y - 27 =10y +x
10x+y-10y-x=27
9x-9y =27
Divide by 9
X-y=3
Subs value of x in eqn 1
You will get the answer.
Thanks for asking such a great question. Say thanks to me if you are satisfied. Please mark me as Brainliest.
No at one's place be y
Original no be 10x +y
No obtain by reversing the digits 10y +x
According to the given condition
X +y =8
X=8-y eqn 1
According to second condition
10x +y - 27 =10y +x
10x+y-10y-x=27
9x-9y =27
Divide by 9
X-y=3
Subs value of x in eqn 1
You will get the answer.
Thanks for asking such a great question. Say thanks to me if you are satisfied. Please mark me as Brainliest.
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