A number consists of two digits whose sum is 9 if the digits are reversed the new number is 3/8 of first number. find the number
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Let the one's digit no. =x
so, tens digit no. =9-x
No formed:
x+10(9-x)
x+ 90 -10x
90-9x
After interchanging
Ones digit = 9-x
tens digit =x
New no formed:
9-x+ 10(x)
9-x+10x
9-9x
ATQ
3/8(90-9x) = 9-9x
135/4-27x/8=9-9x
9x -27x/8=9-135/4
The question is wrong the answer will be in negative.
so, tens digit no. =9-x
No formed:
x+10(9-x)
x+ 90 -10x
90-9x
After interchanging
Ones digit = 9-x
tens digit =x
New no formed:
9-x+ 10(x)
9-x+10x
9-9x
ATQ
3/8(90-9x) = 9-9x
135/4-27x/8=9-9x
9x -27x/8=9-135/4
The question is wrong the answer will be in negative.
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