Question

a number consists of two digits whose sum is 9. if three times the number is equal to eight times the number formed by interchanging the digits, find the number...............plz solve this ​

Answer 1

Let the number be 10x+y

X+y= 9

3(10x+y)=8(10y+x)

30x+3y= 80y+8x

22x=77y

X=7y/2

7y/2 + y = 9

Y=2

X=7

The number is 72

Please mark my answer as the brainliest

Answer 2

Answer:

Step-by-step explanation:

Let the ten's digit be x.

Let the unit's digit be y.

So, x+y=9

So, y=9−x

The actual number is =10x+y

According to the question,

10y+x−2(10x+y)=18

10y+x−20x−2y=18

8y−19x=18

8(9−x)−19x=18 [ Substituting the value of y ]

72−8x−19x=18

72−18−27x=0

54=27x

x=2

So,

y=9−2

y=7

So, the original number is 2×10+7=27