Question

A number consists of two digits whose sum is 9,when 27 is added to this number,the digits interchange their places. The number is……………

Solve this question using one variable.​

Answer 1

SOLUTION ::

Let unit place = b, ten place = a

So the number is 10a+b

Now by the given condition

a+b= 9 - - - - - - - - (1)

when number’s digits are reversed then resulting number is 10b + a

Since the number formed by reversing the digits is less than the original number by 9

(10b + a ) - ( 10a +b ) = 27

➙ 9a - 9b = - 27

➙ a - b = - 3 - - - - - - - (2)

Adding Equation (1) & Equation (2)

2a = 6

➙ a = 3

From Equation (1)

b = 9 - 3 = 6

So the original number is = (10×3) + 6 = 36

Answer 2

Answer:

63.

Step-by-step explanation:

Let the two number be A,B

So, the two digit number,will be 10 A+B.

A-B=3     ----------------------------(1)

10 A+B-27=10 B+A

A-B=3    -----------------------------(2)

On solving (1) and (2), we get

A=6

Submit this value (2) on we get,

B=9-6=3

On submitting the value in above equation we get,

10 A+B

=10*6+3

=63

So, the number is 63.

Hope this will helps:)